Torque and Angular Momentum

Useful Equations

  • Linear Velocity $v$ ($m/s$):
    • $v = [\omega]_\times r$

  • Linear Acceleration $a$ ($m/s^2$):
    • $a = [\alpha]_{\times} r$

  • Angular Velocity $\omega$ ($rad/s$):
    • $\omega = [r]_\times v$

  • Angular Acceleration $\alpha$ ($rad/s^2$):
    • $\alpha = [r]_\times a$

  • Torque $\tau$ ($N \cdot m$):
    • $\tau = [r]_\times F$

  • Angular Inertia $\mathcal{I}$ ($kg \cdot m^2$):
    • $\mathcal{I} = mr^2$

  • Momentum $p$ ($kg \cdot m/s$):
    • $p = mv$

  • Angular Momentum $\mathcal{L}$ ($kg \cdot m^2/s$):
    • $\mathcal{L} = \mathcal{I}\omega$

  • $\mathcal{L} = [r]_\times p = mr^2 \mathbf{\omega}$
  • $\tau = \mathcal{I} \alpha$
  • $\tau = \frac{d\mathcal{L}}{dt}$

Angular Momentum

Though there are lots of equations expressing relations between different quantities, the real cause to make a object rotate is a force on it. So like:

  1. Give a force $F$ at $r$
  2. We get a torque $\tau = [r]_\times F$
  3. We get angular acceleration $\alpha = \tau / \mathcal{I}$
  4. The object starts to rotate and rotation speed $\omega = 0 + \alpha t$
  5. Remove the force
  6. Torque becomes 0
  7. Angular Momentum stays not changed as $\frac{d\mathcal{L}}{dt} = 0$.
  8. If we reduce $r$, $\omega$ will increase as $\mathcal{L} = mr^2\omega$

Based on steps described above, we need to know the force $F$ and $\mathcal{I}$. Here is a list of examples for momentum of inertia.

In the code below, we put $F_0$ and $F_1$ onto the object and let it rotate. And it also shows $F_1$ doesn't really change rotation axis since it is much smaller than $F_0$. This is exactly how gyroscope works. We make a disk rotate very very fast so it will keep its angular momentum not changed.

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This blog is converted from torque.ipynb
Written on January 2, 2022